Carlos Beltran expected to return to Yankees on Thursday

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Some good news here for the 29-28 Yankees.

According to MLB.com’s Bryan Hoch, veteran outfielder Carlos Beltran will meet up with the Yankees on Thursday in Oakland and could be activated from the disabled list for Thursday afternoon’s series-finale against the A’s.

Beltran has been hitting and fielding in games at extended spring training for the past several days and has experienced no major discomfort in his right elbow. He’s been on the shelf since being diagnosed with painful bone spurs in mid-May. The initial worry was the Beltran might need surgery to correct the problem, but he’s going to try to play through it.

Beltran was batting .234/.286/.430 with five home runs and 15 RBI over his first 33 games in pinstripes.

He signed a three-year, $45 million free agent contract with New York this past offseason.

Clay Buchholz makes first major league start in over a year

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The Diamondbacks selected the contract of pitcher Clay Buchholz from Triple-A Reno ahead of Sunday’s game against the Mets. It marked Buchholz’s first major league start since April 11 last season (also against the Mets) when he was a member of the Phillies. Shortly after that start, he was diagnosed with a partial tear of his flexor pronator mass and he ended up not being able to pitch the rest of the season.

Buchholz signed a minor league deal with the Royals but he opted out of his contract at the beginning of this month. The Diamondbacks signed him to a minor league deal a few days later, needing depth with a depleted starting rotation. Buchholz made two starts for Reno before getting the call Sunday.

Buchholz, 33, pitched well on Sunday against the Mets, lasting five innings and limiting the opposition to a run on two hits and a walk with two strikeouts. His only blemish was allowing a solo home run to Amed Rosario leading off the sixth. He was immediately relieved by T.J. McFarland afterwards.

It is not yet clear if Buchholz will get another turn through the D-Backs’ rotation.