When the Cubs beat the Braves 1-0 on Wednesday, they did it sending a total of 26 men to the plate. It was the first time since 2007 that a team had won a nine-inning game without every spot in the order getting three plate appearances.
Of course, to pull off such a feat a team needs to be at home, meaning it wouldn’t have to bat in the ninth. It would have to score at least one run, meaning the fewest number of plate appearances the team could have is 25. The Cubs had 26 today.
What’s really incredible is that the Cubs actually had five hits. However, the first two singles were erased on double plays and Starlin Castro was thrown out at home trying to stretch a triple into an inside-the-park home run. As a result, Tim Hudson faced the minimum through six.
The Cubs went on to get their run in the seventh on a single, a sac bunt, a groundout and another single. The first runner scored, while the second was left on base, the lone runner left on base for the team. The Cubs then went down in order in the eighth before holding on to win 1-0.
The last team to win a nine inning game while sending 26 men to the plate was the Tigers, against the Indians, on Aug. 21, 2007. They won 2-1 on a pair of solo homers from Magglio Ordonez and Carlos Guillen.
The 1992 Braves were the last team to win a nine-inning game sending 25 men to the plate. They beat the Pirates 1-0 on July 25 on a David Justice homer, the only hit allowed by Danny Jackson.